Question

Divide −72a⁴b⁵c⁸ by −9a²b²c³.

Answer 1

$$\begin{gathered} \frac{-72a^4{b}^5{c}^8}{-9a^2{b}^2{c}^3} \\ =\frac{-72\times a\times a\times a\times a\times b\times b\times b\times b\times b\times c\times c\times c\times c\times c\times c\times c\times c}{-9\times a\times a\times b\times b\times c\times c\times c} \\ =8a^{(4-2)}{b}^{(5-2)}{c}^{(8-3)} \\ =8a^2{b}^3{c}^5 \end{gathered}$$