The correct option is A 30 and 50
Let the two numbers be x and y
Given,
x+y=80 (i) and
5x=3y
⟹x=3y5 (ii)
Putting the value of x in equation (i) we get,
x+y=80
⟹3y5+y=80
⟹3y+5y5=80
⟹8y=400
⟹y=50
Putting the value of y in equation (i) we get,
x+y=80
⟹x+50=80
⟹x=80−50
⟹x=30
∴x=30,y=50