Question

Divide $(a^{2}bc+a{b}^{2}c+ab{c}^2)$ by $5abc$.

• A. $\frac{(a+b+c)}{5}$
  
• B. $5(a+b+c)$
• C. $\frac{(a+b+c)}{5abc}$
  
• D. $\frac{abc(a+b+c)}{5}$
  

Answer 1

The correct option is A $\frac{(a+b+c)}{5}$


First, let's factorize $(a^{2}bc+a{b}^{2}c+ab{c}^2)$

Taking ${}^{\prime }ab{c}^{\prime }$ common from the first three terms:
$(a^{2}bc+a{b}^{2}c+ab{c}^2)$
$=abc(a+b+c)$

Now, let's divide $abc(a+b+c)$ by $5abc$:
$=\frac{abc(a+b+c)}{5abc}$
Cancelling out the common factor $abc$ from the Numerator and Denominator:
$=\frac{(a+b+c)}{5}$


$(a^{2}bc+a{b}^{2}c+ab{c}^2)$ when divided by $5abc$ would be equal to $\frac{(a+b+c)}{5}$.

Therefore, option (a.) is the correct answer.