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Question

Divide:
a) (x3+1)by(x+1)
b) (4x2+3x+12)by(2x+1)

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Solution

(i)(x3+1)x+1

=(x+1)(x2x+1)(x+1)

=x2x+1

x3+1x+1=x1x+1

(ii)4x2+3x+1/22x+1

=(2x+1)(2x+1/2)(2x+1/2)

=2x+1/2

4x2+3x+1/22x+1=2x+12


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