Divide a line segment AB of any length putting a point C such that $\frac{A C}{C B}$ is 3:1.

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Solution

Here, the ratio $\frac{A C}{C B}$ = 3:4.

Therefore, the number of arcs to be cut is 3+1 = 4.

Procedure:

1. Draw a line segment $A B$ . Draw a ray from $A$ in any direction.

2. On that ray, mark 4 arcs of same length.Name them as $A_{1}$ to $A_{4}$ .

3. Join $A_{4}$ and $B$ .

4. Draw a line parallel to $A_{4} B$ passing through $A_{3}$ such that it cuts line segment at C.

5. Now, the line segment $A B$ is divided by $C$ in the ratio $3 : 4$ .

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Divide a line segment AB of any length putting a point C such that ACCB is 3:1.

Divide a line segment AB of any length putting a point C such that $\frac{A C}{C B}$ is 3:1.