Divide a line segment of length $9 c m$ internally in the ratio $4 : 3$ .

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Solution

Steps

Step 1: first draw line segment $A B = 9 c m$

Step 2: draw a ray $A X$ making an acute angle $∠ B A X = 60$ with $A B$

Step 3: draw a ray $B Y$ parallel to $A X$ by making an acute angle $∠ A B Y = ∠ B A X$

Step 4: mark points $A_{1}, A_{2}, A_{3}, A_{4}$ on $A X$ , 4 points $B_{1}, B_{2}, B_{3}$ on $B Y$

Step 5: Join $A_{4} B_{3}$

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Similar questions

Divide a line segment AB of length 9 cm in the ratio 4:4 at C. Now, divide the new line segment AC in the ratio 3:2 at M.

(i) Draw a line segment of length 8 cm and divide it internally in the ratio 4 : 5.

(ii) Draw a line segment of length 7.6 cm and divide it in the ratio 5 : 8 Measure the two parts.

14 c m

2 : 5

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