Question

Divide:
acx² + (bc + ad)x + bd by (ax + b)

Answer 1

$$\begin{gathered} \frac{ac{x}^{\mathit{2}}\mathit{+}\mathit{(}bc\mathit{+}ad\mathit{)}x\mathit{+}bd}{\mathit{(}ax\mathit{+}b\mathit{)}} \\ \mathit{=}\frac{ac{x}^{\mathit{2}}\mathit{+}bcx\mathit{+}adx\mathit{+}bd}{\mathit{(}ax\mathit{+}b\mathit{)}} \\ \mathit{=}\frac{cx\mathit{(}ax\mathit{+}b\mathit{)}\mathit{+}d\mathit{(}ax\mathit{+}b\mathit{)}}{\mathit{(}ax\mathit{+}b\mathit{)}} \\ \mathit{=}\frac{\mathit{(}ax\mathit{+}b\mathit{)}\mathit{(}cx\mathit{+}d\mathit{)}}{\mathit{(}ax\mathit{+}b\mathit{)}} \\ \mathit{=}\mathit{}cx\mathit{+}d \end{gathered}$$