Divide and verify $16 + 8 x + x^{6} - 8 x^{3} - 2 x^{4} + x^{2}$ by $x + 4 - x^{3}$

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Solution

Thus $\frac{16 + 8 x + x^{6} - 8 x^{3} - 2 x^{4} + x^{2}}{x + 4 - x^{3}} = - x^{3} + x + 4$

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Similar questions

16 + 8 x - x^{6} - 8 x^{3} - 2 x^{4} + x^{2}

x + 4 - x^{3}

16 + 8 x + x^{6} - 8 x^{3} - 2 x^{4} + x 2

x + 4 - x^{3}

- x^{3} + x + 4

- x^{6} + 2 x^{4} + 4 x^{3} + 2 x^{2} by \sqrt{2} x^{2}

x^{3} - 3 x^{2} + 3 x - 5

x - 1 - x^{2}

p (x) = 2 x^{4} - 3 x^{3} - 5 x^{2} + 8 x - 3

p (x)

(x - \frac{3}{2})

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