Divide as directed- 52pqr-p - q-q - r-r - p- - 104pq-q - r-r - p- - Maths Q-A

Here,= 52pqr(p+q )(q+r)(r+p) /104pq(q+r)(r+p)0ex0ex=52pq/104pq×(q+r)(r+p) /(q+r)(r+p) × r(p+q )0ex0ex=1/2× 1× r(p+q )0ex0ex=𝐫(𝐩+𝐪)/2Thus,52pqr(p + q)(q + r)(r + ...

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Byju's Answer

Standard XII

Mathematics

Addition Rule of Differentiation

Divide as dir...

Question

Divide as directed: $52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$

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Solution

Here,
$= \frac{52 p q r (p + q) (q + r) (r + p)}{104 p q (q + r) (r + p)} = \frac{52 p q}{104 p q} \times \frac{(q + r) (r + p)}{(q + r) (r + p)} \times r (p + q) = \frac{1}{2} \times 1 \times r (p + q) = \frac{r (p + q)}{2}$
Thus,
$52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$ $= \frac{r (p + q)}{2}$

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Similar questions

Divide as directed.

(i) $5 (2 x + 1) (3 x + 5) \div (2 x + 1)$

(ii) $26 x y (x + 5) (y - 4) \div 13 x (y - 4)$

(iii) $52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$

(iv) $20 (y + 4) (y^{2} + 5 y + 3) \div 5 (y + 4)$

(v) $x (x + 1) (x + 2) (x + 3) \div x (x + 1)$

Question 5(a)
Add :p ( p - q ), q (q - r ) and r (r - p ).

If |\begin{matrix} p & b & c \\ a & q & c \\ a & b & r \end{matrix}| = 0, find the value of \frac{p}{p - a} + \frac{q}{q - b} + \frac{r}{r - c}, p \neq a, q \neq b, r \neq c .

Question 4(iii)
Divide as directed
$52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$

Q. Divide :

52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)

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Divide as directed:52pqr(p+q)(q+r)(r+p)÷104pq(q+r)(r+p)

Here,=52pqr(p+q)(q+r)(r+p)104pq(q+r)(r+p)=52pq104pq×(q+r)(r+p)(q+r)(r+p)×r(p+q)=12×1×r(p+q)=r(p+q)2Thus,52pqr(p+q)(q+r)(r+p)÷104pq(q+r)(r+p) =r(p+q)2

Divide as directed: $52 p q r (p + q) (q + r) (r + p) \div 104 p q (q + r) (r + p)$