1
Question
Divide by long division method
2x4+x3−27x2−36x+1552x−5
2x4+x3−27x2−36x+1552x−5
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Solution
We divide 2x4+x3−27x2−36x+155 by (2x−5) as shown in the above image:
From the division, we observe that the quotient is x3+3x2−6x−33 and the remainder is −10.
Hence, the quotient is x3+3x2−6x−33 and the remainder is −10 on dividing the polynomial 2x4+x3−27x2−36x+155 by 2x−5.
We divide 2x4+x3−27x2−36x+155 by (2x−5) as shown in the above image:
From the division, we observe that the quotient is x3+3x2−6x−33 and the remainder is −10.
Hence, the quotient is x3+3x2−6x−33 and the remainder is −10 on dividing the polynomial 2x4+x3−27x2−36x+155 by 2x−5.
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