Divide $(7 y^{2} - 21 y + 2 y z - 6 z)$ by $(7 y + 2 z)$

z - 3

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7 y + 2 z

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y - 3

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y + 3

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Solution

The correct option is C $y - 3$
$7 y^{2} - 21 y + 2 y z - 6 z = 7 y (y - 3) + 2 z (y - 3)$
$= (y - 3) (7 y + 2 z)$

$∴ (7 y^{2} - 21 y + 2 y z - 6 z) \div (7 y + 2 z)$

$= \frac{(7 y^{2} - 21 y + 2 y z - 6 z)}{(7 y + 2 z)}$

$= \frac{(y - 3) (7 y + 2 z)}{(7 y + 2 z)} = y - 3$

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