Question

Divide: $8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)÷2x^2{y}^2{z}^2$

• A. $4(y+z)$
• B. $4\left(x\right)$
• C. $4(x+y+z)$
• D. $4x+4y+z$

Answer 1

Answer: (C)

$4(x+y+z)$

$8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)÷2x^2{y}^2{z}^2$

$=\frac{8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)}{2x^2{y}^2{z}^2}$

$=\frac{8x^2{y}^2{z}^2(x+y+z)}{2x^2{y}^2{z}^2}$

$=4(x+y+z)$