Divide: $(3 x + 2 y + x y + 6)$ by $(y + 3)$

(x + 2)

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(x + 3)

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(y + 3)

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(y + 2)

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Solution

The correct option is A $(x + 2)$
$(3 x + 2 y + x y + 6) \div (y + 3)$
$= 3 x + x y + 2 y + 6$
$= x (3 + y) + 2 (y + 3)$
$= (x + 2) (y + 3)$ .....(i)
$∴ (3 x + 2 y + x y + 6) \div (y + 3) = \frac{(3 x + 2 y + x y + 6)}{(y + 3)}$
$= \frac{(x + 2) (y + 3)}{(y + 3)} = (x + 2)$

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Divide: (3x+2y+xy+6) by (y+3)

The correct option is A (x+2)(3x+2y+xy+6)÷(y+3)=3x+xy+2y+6=x(3+y)+2(y+3)=(x+2)(y+3) .....(i)∴(3x+2y+xy+6)÷(y+3)=(3x+2y+xy+6)(y+3)=(x+2)(y+3)(y+3)=(x+2)

Divide: $(3 x + 2 y + x y + 6)$ by $(y + 3)$

The correct option is A $(x + 2)$
$(3 x + 2 y + x y + 6) \div (y + 3)$
$= 3 x + x y + 2 y + 6$
$= x (3 + y) + 2 (y + 3)$
$= (x + 2) (y + 3)$ .....(i)
$∴ (3 x + 2 y + x y + 6) \div (y + 3) = \frac{(3 x + 2 y + x y + 6)}{(y + 3)}$
$= \frac{(x + 2) (y + 3)}{(y + 3)} = (x + 2)$