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Question

Divide each of the following polynomials by synthetic division method and also by
linear division method. Write the quotient and the remainder.

(i) 2m2 - 3m + 10 ÷ m - 5 (ii) x4 + 2x3 + 3x2 + 4x + 5 ÷ x + 2 (iii) y3 - 216 ÷ y - 6

(iv) 2x4 + 3x3 + 4x - 2x2 ÷ x + 3 (v) x4 - 3x2 - 8 ÷ x + 4 (vi) y3 - 3y2 + 5y - 1 ÷ y - 1

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Solution

(i)
Synthetic Division:

Dividend = 2m2-3m+10

Divisor = m-5

Opposite of −5 = 5




The coefficient form of the quotient is (2, 7).

∴ Quotient = 2m + 7 and Remainder = 45

Linear Method:

2m2-3m+10=2mm-5+10m-3m+10=2mm-5+7m-5+35+10=m-5×2m+7+45
(ii)
Synthetic Division:

Dividend = x4+2x3+3x2+4x+5

Divisor = x+2

Opposite of 2 = −2



The coefficient form of the quotient is (1, 0, 3, −2).

∴ Quotient = x3 + 3x − 2 and Remainder = 9

Linear Method:

x4+2x3+3x2+4x+5=x3x+2+3xx+2-6x+4x+5=x3x+2+3xx+2-2x+5=x3x+2+3xx+2-2x+2+4+5=x+2×x3+3x-2+9
(iii)
Synthetic Division:

Dividend = y3-216=y3+0y2+0y-216

Divisor = y-6

Opposite of −6 = 6



The coefficient form of the quotient is (1, 6, 36).

∴ Quotient = y2 + 6y + 36 and Remainder = 0

Linear Method:

y3-216=y2y-6+6y2-216=y2y-6+6yy-6+36y-216=y2y-6+6yy-6+36y-6+216-216=y2y-6+6yy-6+36y-6=y-6×y2+6y+36
(iv)
Synthetic Division:

Dividend = 2x4+3x3+4x-2x2=2x4+3x3-2x2+4x+0

Divisor = x+3

Opposite of 3 = −3



The coefficient form of the quotient is (2, −3, 7, −17).

∴ Quotient = 2x3 − 3x2 + 7x − 17 and Remainder = 51

Linear Method:

2x4+3x3-2x2+4x=2x3x+3-6x3+3x3-2x2+4x=2x3x+3-3x2x+3+9x2-2x2+4x=2x3x+3-3x2x+3+7xx+3-21x+4x=2x3x+3-3x2x+3+7xx+3-17x+3+51=x+3×2x3-3x2+7x-17+51
(v)
Synthetic Division:

Dividend = x4-3x2-8=x4+0x3-3x2+0x-8

Divisor = x+4

Opposite of 4 = −4



The coefficient form of the quotient is (1, −4, 13, −52).

∴ Quotient = x3 − 4x2 + 13x − 52 and Remainder = 200

Linear Method:

x4-3x2-8=x3x+4-4x3-3x2-8=x3x+4-4x2x+4+16x2-3x2-8=x3x+4-4x2x+4+13xx+4-52x-8=x3x+4-4x2x+4+13xx+4-52x+4+208-8=x+4×x3-4x2+13x-52+200
(vi)
Synthetic Division:

Dividend = y3-3y2+5y-1

Divisor = y-1

Opposite of −1 = 1



The coefficient form of the quotient is (1, −2, 3).

∴ Quotient = y2 − 2y + 3 and Remainder = 2

Linear Method:

y3-3y2+5y-1=y2y-1+y2-3y2+5y-1=y2y-1-2yy-1-2y+5y-1=y2y-1-2yy-1+3y-1+3-1=y-1×y2-2y+3+2

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