Divide $g (t) = 4 t^{3} + 4 t^{2} - t - 1$ by $f (t) = 2 t + 1$ find $q$ and $R$ .

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Solution

$g (t) = 4 t^{3} + 4 t^{2} - t - 1 f (t) = 2 t + 1$
$∴ q = 2 t^{2} + t - 1$ and $R = 0$

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Find the remainder when q(t) = 4t³ + 4t² – t - 1 is divided by 2t + 1

Is 2t+1 a factor of 4 $t^{3}$ +4 $t^{2}$ -t-1?

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