Question

Divide:
(i) $1\mathrm{by}\frac{1}{2}$
(ii) $5\mathrm{by}\frac{-5}{7}$
(iii) $\frac{-3}{4}\mathrm{by}\frac{9}{-16}$
(iv) $\frac{-7}{8}\mathrm{by}\frac{-21}{16}$
(v) $\frac{7}{-4}\mathrm{by}\frac{63}{64}$
(vi) $0\mathrm{by}\frac{-7}{5}$
(vii) $\frac{-3}{4}\mathrm{by}-6$
(viii) $\frac{2}{3}\mathrm{by}\frac{-7}{12}$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)1÷\frac{1}{2}=1\times \frac{2}{1}=2 \\ \left(\mathrm{ii}\right)5÷\frac{-5}{7}=5\times \frac{7}{-5}=-7 \\ \left(\mathrm{iii}\right)\frac{-3}{4}÷\frac{9}{-16}=\frac{-3}{4}\times \frac{-16}{9}=\frac{-3}{4}\times \frac{-4\times 4}{3\times 3}=\frac{4}{3} \\ \left(\mathrm{iv}\right)\frac{-7}{8}÷\frac{-21}{16}=\frac{-7}{8}\times \frac{-16}{21}=\frac{-7}{8}\times \frac{-8\times 2}{7\times 3}=\frac{2}{3} \end{gathered}$$

$$\begin{gathered} \left(\mathrm{v}\right)\frac{7}{-4}÷\frac{63}{64}=\frac{7}{-4}\times \frac{64}{63}=\frac{-7}{4}\times \frac{4\times 16}{7\times 9}=\frac{-16}{9} \\ \left(\mathrm{vi}\right)0÷\frac{-7}{5}=0\times \frac{-7}{5}=0 \\ \left(\mathrm{vii}\right)\frac{-3}{4}÷-6=\frac{-3}{4}\times \frac{-1}{6}=\frac{-3}{4}\times \frac{-1}{2\times 3}=\frac{1}{8} \\ \left(\mathrm{viii}\right)\frac{2}{3}÷\frac{-7}{12}=\frac{2}{3}\times \frac{-12}{7}=\frac{2}{3}\times \frac{-4\times 3}{7}=\frac{-8}{7} \end{gathered}$$