Question

Divide:
(i) $16\sqrt{6}\mathrm{by}4\sqrt{2}$
(ii) $12\sqrt{5}\mathrm{by}4\sqrt{3}$
(iii) $18\sqrt{21}\mathrm{by}6\sqrt{7}$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)\frac{16\sqrt{6}}{4\sqrt{2}}=\frac{16\sqrt{2}\sqrt{3}}{4\sqrt{2}}=4\sqrt{3} \\ \left(\mathrm{ii}\right)\frac{12\sqrt{15}}{4\sqrt{3}}=\frac{12\sqrt{5}\times \sqrt{3}}{4\sqrt{3}}=3\sqrt{5} \\ \left(\mathrm{iii}\right)\frac{18\sqrt{21}}{6\sqrt{7}}=\frac{18\sqrt{7}\sqrt{3}}{6\sqrt{7}}=3\sqrt{3} \end{gathered}$$