Divide

i) $48 x^{4}$ by $12 x^{2} y$

ii) $24 a^{2} b^{2} c$ by $4 a b$ [2 MARKS]

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Solution

Application: 1 Mark each

i) $\frac{48 x^{4}}{12 x^{2} y}$

$= 4 x^{2} y^{- 1}$

ii) $\frac{24 a^{2} b^{2} c}{4 a b}$

$= 6 a b c$

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Divide

$i .) 4 x^{3} + 6 x^{2} + 12 x$ by $2 x$

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a^{2} + 4 b^{2} - 3 a + 6 b - 4 a b

Factorise by grouping method:

$a^{2} + 4 b^{2} - 3 a + 6 b - 4 a b$

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