Question

Divide:$(15y^4-16y^3+9y^2-\frac{1}{3}y-\frac{50}{9})$ by $(3y-2)$

Answer: $5y^3+2y^2-\frac{13}{3}y+\frac{25}{9}$

• A. True
• B. False

Answer 1

The correct option is B False

$3y-2$ $\overline{)15y^4-16y^3+9y^2-\frac{1}{3}y-\frac{50}{9}(}$ $5y^3-2y^2+\frac{5}{3}y+1$

$-(15y^4-10y^3)$

$\overline{-6y^3+9y^2}$

$-(-6y^3+4y^2)$

$\overline{5y^2-\frac{1}{3}y}$

$-(5y^2-\frac{10}{3}y$

$\overline{3y-\frac{50}{9}}$

$-(3y-2)$

$\overline{-\frac{32}{9}}$

So, the given answer is FALSE.