25×−103=−43
Therefore, reciprocal of −43 is −34
Also,
(12−13)=3−26=16 [LCM of 2 and 3 is 6].
Hence, ATQ,
⇒−34÷16
=−34×6
=−92
=−412
Hence, reciprocal of 25×−103 divided by (12−13)=−412.
Divide 3x3−2x2+5 by x2−1
The remainder obtained when (11+22+33+44+55+…1010) is divided by 4 is