Question

Divide $Rs.6000$ into two parts so that the simple interest on the first part for $9$ months at $12\%$ annum is equal to the simple interest on the second part for $1\frac{1}{2}$ years at $10\%$ per annum.

Answer 1

Let one part is $x$ and other part is $(6000-x)$

Now,

S.I on first part =S.I. on second part

$x\times \frac{12}{100}\times \frac{9}{12}=(6000-x)\times \frac{10}{100}\times \frac{3}{2}$

$\therefore x=3750$

and $(6000-x)$

$\Rightarrow 6000-3750=2250$

Therefore two parts of $6000$ are $3750$ and $2250$.