Question

Divide sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their differences.

Answer 1

The sum of $\frac{65}{12}$ and $\frac{8}{3}$

$=\frac{65}{12}+\frac{8}{3}$

$=\frac{65}{12}+\frac{8\times 4}{3\times 4}$

$=\frac{65}{12}+\frac{32}{12}$

$=\frac{65+32}{12}=\frac{97}{12}$

Difference of $\frac{65}{12}$ and $\frac{8}{3}$

$=\frac{65}{12}-\frac{8}{3}$

$=\frac{65}{12}-\frac{8\times 4}{3\times 4}$

$=\frac{65}{12}-\frac{32}{12}$

$=\frac{65-32}{12}=\frac{33}{12}$

According to the question,

$\frac{97}{12}÷\frac{33}{12}$

$=\frac{97}{12}\times \frac{12}{33}$

$=\frac{97}{33}$