Question

Divide the binomial by the monomial. Write the quotient and the remainder.

(6) 18b⁴ + 13b³; 2b²

Answer 1

(18b⁴ + 13b³ ) ÷ 2b² can be shown as,

$$\begin{gathered} 9b^2+\frac{13}{2}b \\ 2b^2\overline{)18b^4+13b^3} \\ \underline{-18b^4} \\ 0+13b^3 \\ +13b^3 \\ \underline{-} \\ \underline{0} \end{gathered}$$

So, the quotient of the division is $9b^2+\frac{13}{2}b$ and the remainder is 0