Divide the first polynomial by the second polynomial and express as Divided = Divisor x quotient + Reminder
$x^{3} - 5 x^{2} + 4 x + 8; x + 2$

(x + 2) (x^{2} - 7 x + 18) - 24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 2) (x^{2} - 6 x + 18) - 28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 2) (x^{2} - 8 x + 18) - 28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + 2) (x^{2} - 7 x + 18) - 28

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $(x + 2) (x^{2} - 7 x + 18) - 28$
$x^{3} - 5 x^{2} + 4 x + 8 \div x + 2$
$x^{2} - 7 x + 18$
$x + 2$ $x^{3} - 5 x^{2} + 4 x + 8$
$x^{3} + 2 x^{2}$
- -
$- 7 x^{2} + 4 x$
$- 7 x^{2} - 14 x$
+ +
$18 x + 8$
$18 x + 36$
- -
$- 28$
Therefore,
$x^{3} - 5 x^{2} + 4 x + 8 = (x + 2) (x^{2} - 7 x + 18) - 28$

Suggest Corrections

Similar questions

Find the quotient when polynomial $2 x^{3} + 6 x^{2} + 7 x + 60$ is divide by $2 x^{2} - 2 x + 15$

q (x)

(x^{4} + x^{3} - 2 x^{2} + x - 1)

(x - 1)

-

(8 x^{4} + 10 x^{3} - 5 x^{2} - 4 x + 1)

(2 x^{2} + x - 1)

2 x^{3} + 2 x^{2} + 2

x - 3

Join BYJU'S Learning Program