Divide the folloiwng polymonials
$p (x) = x^{3} + 3 x^{2} + 3 x + 1$ by $x - 1$

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Solution

$x - 1) ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ x^{3} + 3 x^{2} + 3 x + 1 (x^{2} + 4 x + 7$
$x^{3} - x^{2} - ------ -$
$4 x^{2} + 3 x + 1$
$4 x^{2} - 4 x - -------- -$
$7 x + 7$
$7 x - 7 - ----- -$
$14 - - -$

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Similar questions

p (x) = x^{3} + 3 x^{2} + 3 x + 1

x

x^{3} - 3 x^{2} + 3 x - 1

x - 1

Divide $(3 x^{2} - x^{3} - 3 x + 5)$ by $(x - 1 - x^{2})$

p (x) = x^{3} + 3 x^{2} + 3 x + 1

x = - \frac{1}{2}

p (a) x = - \frac{1}{2} = 0

x = \frac{1}{2}

p (\frac{1}{2}) = {(\frac{1}{2})}^{3} + 3 {(\frac{1}{2})}^{2} + 3 (\frac{1}{2}) + 1

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