Divide the following redox reactions into oxidation and reduction half reactions.

(iii) Cl $_{2}$ + 2Br $^{-}$ $\to$ Br $_{2}$ + 2Cl $^{-}$

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Solution

The redox reactions into oxidation and reduction half reactions:-

Oxidation half reaction

2Br- $\to$ Br $_{2}$ + 2e $^{-}$ (Loss of two electrons)

Reduction half reaction

Cl $_{2}$ + 2e $^{-}$ $\to$ 2Cl $^{-}$ - (Gain of two electrons)

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