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Oxidising Reagent and Reducing Reagent

Divide the fo...

Question

Divide the following redox reactions into oxidation and reduction half reactions.

(iv) Sn $^{2 +}$ + 2Hg $^{2 +}$ $\to$ Sn $^{4 +}$ + Hg $_{2}$ $^{2 +}$

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Solution

The redox reactions into oxidation and reduction half reactions:-

Oxidation half reaction

Sn $^{2 +}$ $\to$ Sn $^{4 +}$ + 2e $^{-}$ (Loss of two electrons)

Reduction half reaction

2Hg $^{2 +}$ + 2e $^{-}$ $\to$ Hg2 $^{2 +}$ (Gain of two electrons)

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Similar questions

Divide the following redox reactions into oxidation and reduction half reactions.

(i) $Z n + P b^{2} \to Z n^{2} + P b$

(ii) $Z n + C u^{2 +} \to Z n^{2} + C u$

(iii) $C l_{2} + 2 B r^{-} \to B r_{2} + 2 C l^{-}$

^{+}

\to

^{2 +}

{S n}^{2 +} + {2 H g}^{2 +} ⟶ {H g}_{2}^{2 +} + {S n}^{4 +}

{G e}^{2 +} + {P b}^{4 +} ⟶ {p b}^{2 +} + {G e}^{4 +}

{T 1}^{+} + {G a}^{3 +} ⟶ {G a}^{+} + {T 1}^{3 +}

S n^{4 +} + 2 e^{-} \to S n^{2 +}

C r^{+} + S n^{4 +} \to C r^{3 +} + S n^{2 +}

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