Question

Divide the given polynomial.
8$(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)$ $÷4x^2{y}^2{z}^2$

• A. $2(x-y+z)$
• B. $2(x+y-z)$
• C. $2(x-y-z)$
• D. $2(x+y+z)$

Answer 1

The correct option is D $2(x+y+z)$

We have :
$8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)=\left(8x^2{y}^2{z}^2\right(x+y+z)$

$8(x^3{y}^2{z}^2+x^2{y}^3{z}^2+x^2{y}^2{z}^3)÷4x^2{y}^2{z}^2=\frac{8x^2{y}^2{z}^2(x+y+z)}{4x^2{y}^2{z}^2}=2(x+y+z)$