Divide the given polynomial by the given monomial-2 y3-3 y2-12 y - 3 yA- 1 - 2x2-2 x-3B- 1 - 2C- x2-2 x-3D- 1

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Division of a Monomial by Another Monomial

Divide the gi...

Question

Divide the given polynomial by the given monomial:
$(2 y^{3} + 3 y^{2} + 12 y) \div 3 y$

1/2(x²+2x+3)

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1/2

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(x²+2x+3)

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Solution

The correct option is B
1/2

Divide all the terms of the expression $(2 y^{3} + 3 y^{2} + 12 y)$ separately by $3 y$ .
$\frac{2 y^{3}}{3 y} = \frac{2 y^{2}}{3}$ ;
$\frac{3 y^{2}}{3 y} = y$ ;
$\frac{12 y}{3 y} = 4$ .
Therefore $\frac{(2 y^{3} + 3 y^{2} + 3 y)}{3 y} = \frac{2 y^{2}}{3} + y + 4$

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Divide the given polynomial by the given monomial: (2y3+3y2+12y)÷3y

The correct option is B 1/2 Divide all the terms of the expression (2y3+3y2+12y) separately by 3y. 2y33y=2y23; 3y23y=y; 12y3y=4. Therefore (2y3+3y2+3y)3y=2y23+y+4

Divide the given polynomial by the given monomial:
$(2 y^{3} + 3 y^{2} + 12 y) \div 3 y$

The correct option is B
1/2

Divide all the terms of the expression $(2 y^{3} + 3 y^{2} + 12 y)$ separately by $3 y$ .
$\frac{2 y^{3}}{3 y} = \frac{2 y^{2}}{3}$ ;
$\frac{3 y^{2}}{3 y} = y$ ;
$\frac{12 y}{3 y} = 4$ .
Therefore $\frac{(2 y^{3} + 3 y^{2} + 3 y)}{3 y} = \frac{2 y^{2}}{3} + y + 4$