Evaluate
8(x3y2z2+x2y3z2+x2y2z3)÷4x2y2z2
If x,y,z∈R+ then xyx+y+yzy+z+xzx+z is always
∣∣ ∣∣x+y+2zxyzy+z+2xyzxz+x+2y∣∣ ∣∣=2(x+y+z)3