Divide the line segment $A B = 10 c m$ in $3$ equal parts.

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Solution

Step 1: Draw a line segment $A B$ of length $10 c m$ using a ruler.
Step 2: Draw an acute $∠ C B A$ on one side of line $A B$ .
Step 3: Mark points $B_{1}, B_{2}, B_{3}$ on ray $B C$ such that $B B_{1} = B_{1} B_{2} = B_{2} B_{3}$ .
Step 4: Join $B_{3}$ to $A$ .
Step 5: Draw lines $B_{1} E$ and $B_{2} D$ parallel to $B_{3} A$ and let them intersect $A B$ in points $E$ and $D$ respectively.

Points $D$ and $E$ divide the segment $A B$ in $3$ equal parts.

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