Question

Divide the monomial $81p^3{q}^6$ by $27p^6{q}^3$

• A. $\frac{3q^3}{p^3}$
• B. $\frac{q^3}{p^3}$
• C. $\frac{3q^3}{p^2}$
• D. $\frac{4q^3}{p^3}$

Answer 1

The correct option is A

$\frac{3q^3}{p^3}$

Dividing $81p^3{q}^6$ by $27p^6{q}^3$

= $\frac{81}{27}\times \frac{p^3{q}^6}{p^6{q}^3}$

= $3\times p^{3-6}{q}^{6-3}$

= $\frac{3q^3}{p^3}$