Divide the monomials: $26 p^{2} q^{2}$ by $12 p q$

\frac{13 p q}{3}

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\frac{13 p}{6 q}

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\frac{13 p q}{6}

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\frac{13 p q}{4}

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Solution

The correct option is C $\frac{13 p q}{6}$
$26 p^{2} q^{2} \div 12 p q = \frac{26 p^{2} q^{2}}{12 p q}$

$= \frac{13}{6} \times \frac{p^{2}}{p} \times \frac{q^{2}}{q}$

$= \frac{13}{6} \times p^{2 - 1} \times q^{2 - 1}$

$= \frac{13}{6} \times p \times q$

$= \frac{13 p q}{6}$

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