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Question

Divide the polynomial $$39y^3(50y^2 - 98)$$ by $$36y^2 (5y + 7)$$


Solution

Factorising the polynomial $$39y^3(50y^2-98)$$

we get $$39y^3(50y^2-98)=39\times 2y^3(5y-7)(5y+7)$$

Thus dividing the above polynomial by $$36y^2(5y+7)$$, we get

$$\dfrac{39 \times 2y^3(5y-7)(5y+7)}{36y^2(5y+7)}=\dfrac{13}{6}y(5y-7)$$

Mathematics

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