Question

Divide the polynomial by the binomial. Write your answer in the form: Dividend = divisor × quotient + remainder

(2) 2y³ + 6y² + 12y + 8; y + 1

Answer 1

(2y³ + 6y² + 12y + 8) ÷ (y + 1) can be shown as:

$$\begin{gathered} 2y^2+4y+8 \\ y+1\overline{)2y^3+6y^2+12y+8} \\ 2y^3+2y^2 \\ \underline{--} \\ 4y^2+12y \\ 4y^2+4y \\ \underline{--} \\ 0+8y+8 \\ 8y+8 \\ \underline{--} \\ \underline{0} \end{gathered}$$

Dividend = divisor × quotient + remainder
∴ 2y³ + 6y² + 12y + 8 = (y + 1) (2y² + 4y + 8) + 0