Divide the polynomial $x (3 x^{2} - 108)$ by another polynomial $3 x (x - 6)$

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Solution

To divide the polynomial $x (3 x^{2} - 108)$ by $3 x (x - 6)$
Now, on factorising the polynomial $x (3 x^{2} - 108)$ , we get
$x (3 x^{2} - 108) = 3 x (x^{2} - 36) =$ $3 x (x - 6) (x + 6)$
Thus $\frac{3 x (x - 6) (x + 6)}{3 x (x - 6)} = (x + 6)$

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