Question

Divide the product of $(-33)$ and $3$ by the sum of $(-12)$ and $3$

Answer 1

Product of $(-33)$ and $3$ is $-33\times 3=-99$

Sum of $(-12)$ and $3$ is $-12+3=-9$

So the answer is $-99÷-9=\frac{-99}{-9}=11$