Question

Divide the sum of -1/12 and -4/9 by their difference.

Answer 1

Dear student
$$\begin{gathered} Sum=\frac{-1}{12}+\left(\frac{-4}{9}\right)=\frac{-1}{12}-\frac{4}{9}=\frac{-3-16}{36}=\frac{-19}{36} \\ difference=\frac{-1}{12}-\left(\frac{-4}{9}\right)=\frac{-1}{12}+\frac{4}{9}=\frac{-3+16}{36}=\frac{13}{36} \\ Now,Accordingtoquestion, \\ \frac{sum}{difference}=\frac{{\displaystyle \frac{-19}{36}}}{{\displaystyle \frac{13}{36}}}=\frac{-19}{36}\times \frac{36}{13}=\frac{-19}{13} \end{gathered}$$
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