Question

Divide the sum of $-13/8$ and $5/12$ by their difference.

Answer 1

sum of $\frac{-13}{8}and\frac{5}{12}$

$\Rightarrow \frac{-13}{8}+\frac{5}{12}$

$\Rightarrow \frac{(-13\times 3)+(5\times 2)}{24}$

$\Rightarrow \frac{(-39)+\left(10\right)}{24}$

$\Rightarrow -\frac{29}{24}$

and similarly difference

$\Rightarrow \frac{-13}{8}-\frac{5}{12}$

$\Rightarrow \frac{(-13\times 3)-(5\times 2)}{24}$

$\Rightarrow \frac{(-39)-\left(10\right)}{24}$

$\Rightarrow -\frac{49}{24}$

Now,

$\Rightarrow -\frac{29}{24}÷-\frac{49}{24}$

$\Rightarrow \frac{29}{24}\times \frac{24}{49}$

$=\frac{29}{49}$