Divide the sum of (65/12) and (8/3) by their difference.

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Solution

((65/12) + (8/3)) ÷ ((65/12) – (8/3))

= ((65/12) + (32/12)) ÷ ((65/12) – (32/12))

= (65 + 32)/12 ÷ (65 -32)/12

= (65 + 32)/12 × (12/ (65 – 32)

= (65 + 32)/ (65 – 32)

= (97/33)

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Similar questions

Divide the sum of $\frac{5}{8}$ and $\frac{- 11}{12}$ by the difference of $\frac{3}{7}$ and $\frac{5}{14}$ .

divide the sum of 65/12 and 8/3 by their difference

\frac{65}{12}

\frac{8}{3}

\frac{65}{12}

\frac{12}{7}

Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by thier difference.

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