Question

Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.

Answer 1

$$\begin{gathered} \left(\frac{65}{12}+\frac{8}{3}\right)÷\left(\frac{65}{12}-\frac{8}{3}\right) \\ =\left(\frac{65}{12}+\frac{32}{12}\right)÷\left(\frac{65}{12}-\frac{32}{12}\right) \\ =\left(\frac{97}{12}\right)÷\left(\frac{33}{12}\right) \\ =\frac{97}{12}\times \frac{12}{33} \\ =\frac{97}{33} \end{gathered}$$