Question

Divide the sum of $\frac{-4}{9}$ and $\frac{1}{3}$ by $\frac{5}{6}$.

Answer 1

$(\frac{-4}{9}+\frac{1}{3})÷\frac{5}{6}$

$=\frac{-1}{9}\times \frac{6}{5}$

$=\frac{-2}{15}$