Question

Divide the sum of $-\frac{13}{5}$ and $\frac{12}{7}$ by the product of $-\frac{13}{7}$ and $-\frac{1}{2}$.

Answer 1

Sum of $\frac{-13}{5}\&\frac{12}{7}$ divided by product of $\frac{-13}{7}\&\frac{-1}{2}$

$\Rightarrow$ Sum of $\frac{-13}{5}+\frac{12}{7}=\frac{-13\left(7\right)+12\left(5\right)}{(5\times 7)}=\frac{-91+60}{35}=\frac{-31}{35}$

$\Rightarrow$ Product of $\frac{-13}{7}\&\frac{-1}{2}=\left(\frac{-13}{7}\right)\left(\frac{-1}{2}\right)=\frac{13}{14}$

$\Rightarrow$ Division of $\frac{\left(\frac{-31}{35}\right)}{\left(\frac{13}{14}\right)}=\frac{-31}{35}\times \frac{14}{13}=\frac{-62}{65}$

Hence, solved.