Question

Divide the sum of $\frac{4}{13}$ and $\frac{-3}{2}$ by their product.

Answer 1

Let us consider the problem:

sum of $\frac{4}{13}$ and $\frac{-3}{2}$ is $\frac{4}{13}-\frac{3}{2}=\frac{8-39}{26}$

$\Rightarrow$ $\frac{-31}{26}$

and product $=\frac{4}{13}\times \left(\frac{-3}{2}\right)$

$\Rightarrow$ $\frac{-12}{26}$

therefore,

$=\frac{\frac{-31}{26}}{\frac{-12}{26}}$

$\Rightarrow$ $=\frac{31}{26}\times \frac{26}{12}$

hence,

$=\frac{31}{12}$