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Comparison of Fractions

Divide the su...

Question

Divide the sum of $\frac{12}{5}$ and $\frac{13}{7}$ by the product of $\frac{- 4}{7}$ and $\frac{- 1}{2} .$ The result obtained is :

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Solution

Result $= \frac{\frac{12}{5} + \frac{13}{7}}{\frac{- 4}{7} \times \frac{- 1}{2}} = \frac{\frac{149}{35}}{\frac{4}{14}} = \frac{149}{10}$

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Similar questions

Q. Divide the sum of

- \frac{13}{5}

\frac{12}{7}

by the product of

- \frac{13}{7}

- \frac{1}{2}

Q. Divide the sum of

\frac{5}{12}

\frac{- 17}{24}

by the product of

\frac{2}{5}

\frac{7}{4}

. What is the result?

Divide the sum of $\frac{3}{5}$ and $\frac{- 1}{2}$ by the product of $\frac{- 1}{7}$ and −1.

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Q. Divide the sum of

\frac{4}{13}

\frac{- 3}{2}

by their product.

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