Divide the sum of 13-5 and -12-7 by the product of -31-7 and 1-2

Sum of 13/5 and 12/7 = 13/5 + 12/7 = 91 + ( 60)/35 = 91 60/35 = 31/35 Now, product of 31/7 and 1/ 2 = 31/7×1/ 2 = 31/ 14 = 31/14 ∴31/35÷31/14 = 31/35×14/ ...

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Byju's Answer

Standard VII

Mathematics

Multiplication and Division of Rational Numbers

Divide the su...

Question

Divide the sum of $\frac{13}{5}$ and $\frac{- 12}{7}$ by the product of $\frac{- 31}{7}$ and $\frac{1}{- 2}$

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Solution

Sum of $\frac{13}{5}$ and $\frac{- 12}{7} = \frac{13}{5} + \frac{- 12}{7}$

$= \frac{91 + (- 60)}{35} = \frac{91 - 60}{35} = \frac{31}{35}$

Now, product of $\frac{- 31}{7}$ and $\frac{1}{- 2} = \frac{- 31}{7} \times \frac{1}{- 2}$

$= \frac{- 31}{- 14} = \frac{31}{14}$

$∴ \frac{31}{35} \div \frac{31}{14} = \frac{31}{35} \times \frac{14}{31} = \frac{14}{35}$

$= \frac{14 \div 7}{35 \div 7} = \frac{2}{5}$

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and

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The result obtained is :

Divide the sum of $\frac{3}{5}$ and $\frac{- 1}{2}$ by the product of $\frac{- 1}{7}$ and −1.

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and

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by the product of

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. What is the result?

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Divide the sum of $\frac{5}{8}$ and $\frac{- 11}{12}$ by the difference of $\frac{3}{7}$ and $\frac{5}{14}$ .

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Divide the sum of 135 and −127 by the product of −317 and 1−2

Sum of 135 and −127=135+−127 =91+(−60)35=91−6035=3135 Now, product of −317 and 1−2=−317×1−2 =−31−14=3114 ∴3135÷3114=3135×1431=1435 =14÷735÷7=25

Divide the sum of $\frac{13}{5}$ and $\frac{- 12}{7}$ by the product of $\frac{- 31}{7}$ and $\frac{1}{- 2}$