Divide the sum of 65-12 and 8-3 by their difference-

Sum of 65/12 and 8/3 = 65/12 + 8/3 = 65 + 32/12 = 97/12 Difference of 65/12 and 8/3 = 65/12 8/3 = 65 32/12 = 33/12 ∴97/12÷33/12 = 97/12×12/33 = 97/33 ...

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Byju's Answer

Standard VII

Mathematics

Multiplication and Division of Rational Numbers

Divide the su...

Question

Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.

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Solution

Sum of $\frac{65}{12}$ and $\frac{8}{3} = \frac{65}{12} + \frac{8}{3} = \frac{65 + 32}{12} = \frac{97}{12}$

Difference of $\frac{65}{12}$ and $\frac{8}{3} = \frac{65}{12} - \frac{8}{3} = \frac{65 - 32}{12} = \frac{33}{12}$

$∴ \frac{97}{12} \div \frac{33}{12} = \frac{97}{12} \times \frac{12}{33} = \frac{97}{33}$

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Divide the sum of 6512 and 83 by their difference.

Sum of 6512 and 83=6512+83=65+3212=9712 Difference of 6512 and 83=6512−83=65−3212=3312 ∴9712÷3312=9712×1233=9733

Divide the sum of $\frac{65}{12}$ and $\frac{8}{3}$ by their difference.