Dividing 35 by 79 Given, 35 by 79 =35÷ 79 =35× (multiplicative inverseof 79) =35×9 7 = 351×97 = 7× 5× 91× 7 = 5× 9= 45 Hence, The required answer is ...

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Byju's Answer

Standard VI

Mathematics

Order of Operations

Divide:vii 35...

Question

Divide:
$(v i i)$ $35$ by $\frac{- 7}{9}$

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Solution

Dividing $35$ by $\frac{- 7}{9}$

Given,

$35$ by $\frac{- 7}{9}$

$= 35 \div \frac{- 7}{9}$

$= 35 \times (multiplicative inverseof \frac{- 7}{9})$

$= 35 \times \frac{9}{- 7}$

$= \frac{- 35}{1} \times \frac{9}{7}$

$= - \frac{7 \times 5 \times 9}{1 \times 7}$

$= - 5 \times 9 = - 45$

Hence, The required answer is $- 45$ .

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Similar questions

Verify the following

(i) $\frac{- 12}{5} + \frac{2}{7} = \frac{2}{7} + \frac{- 12}{5}$

(ii) $\frac{- 5}{8} + \frac{- 9}{13} = \frac{- 9}{13} + \frac{- 5}{8}$

(iii) $3 + \frac{- 7}{12} = \frac{- 7}{12} + 3$

(iv) $\frac{2}{- 7} + \frac{12}{- 35} = \frac{12}{- 35} + \frac{2}{- 7}$

Q. Replace

by the correct number in each of the following:
(i)

\frac{2}{7} = \frac{8}{}

(ii)

\frac{3}{5} = \frac{}{35}

(iii)

\frac{5}{8} = \frac{20}{}

(iv)

\frac{45}{60} = \frac{9}{}

(v)

\frac{40}{56} = \frac{}{7}

(vi)

\frac{42}{54} = \frac{7}{}

Q. Multiply:
(i)

\frac{7}{11} by \frac{5}{4}

(ii)

\frac{5}{7} by \frac{- 3}{4}

(iii)

\frac{- 2}{9} by \frac{5}{11}

(iv)

\frac{- 3}{17} by \frac{- 5}{- 4}

(v)

\frac{9}{- 7} by \frac{36}{- 11}

(vi)

\frac{- 11}{13} by \frac{- 21}{7}

(vii)

- \frac{3}{5} by - \frac{4}{7}

(viii)

- \frac{15}{11} by 7

Q. Divide:

(v i i) 4.32

1.2

7 - 3 \frac{5}{9} =

3 \frac{x}{9}

. Find x.

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Order of Operations

Standard VI Mathematics

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Divide: (vii) 35 by −79

Dividing 35 by −79 Given, 35 by −79 =35÷−79 =35×(multiplicative inverseof−79) =35×9−7 =−351×97 =−7×5×91×7 =−5×9=−45 Hence, The required answer is −45.

Divide:
$(v i i)$ $35$ by $\frac{- 7}{9}$