Question

Divide. Write the quotient and the remainder.
(a) $(-48p^4)÷(-9p^2)$
(b) $40m^5÷30m^3$

Answer 1

$\frac{-48p^4}{-9p^2}=\frac{-45p^4-3p^4}{-9p^2}$

Quotient : $5p^2$ Remainder : $-3p^4$

$\frac{40m^5}{30m^5}=\frac{30m^5+10m^5}{30m^3}$

Quotienr $=m^2$, Remainder : $10m^5$