Divide $(x^{2} + 3) (x^{2} - 3) + 9$ by $x^{4}$ [1 MARK]

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Solution

Concept: 1 Mark

$\frac{(x^{2} + 3) (x^{2} - 3) + 9}{x^{4}}$

$U s i n g t h e i d e n t i t y (a + b) (a - b) = (a^{2} + b^{2})$

$= \frac{x^{4} - 9 + 9}{x^{4}}$

$= \frac{x^{4}}{x^{4}}$

$= 1$

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